sum of each digit remain same(piyush constant)

sum of each digit remain same(piyush constant)
piyush constant
SUM OF EACH DIGIT REMAINS "9"(PIYUSH CONSTANT)
Fri, 2006-07-21 22:34 — piyushdadriwala
SUM OF EACH DIGIT REMAINS SAME(9),NINEI AM VERY MUCH FOND OF MATHS ,WHATEVER I AM WRITING HERE IS AMAZING,INTERESTING,LEARN IT,VERY SIMPLE.(FOR ANY NO OF DIGITS)NOW,I HAVE 25 AND 32, MULTIPLE THEM ,NOW YOU CAN MULTIPLE THEM IN FOUR WAYS LIKE THAT(just changing the position)25*32=80052*32=166425*23=57552*23=1196now substract any bigger to any lower you will always get sum of each digit nine.1664-1196=468(4+6+8=18=1+8=9)1664-800=864(8+6+4+18=1+8+=9)1664-575=1089(1+0+8+9=18=1+8=9)1196-800=396(3+9+6=18=1+8=9)1196-575=621(6+2+1=9)800-575=225(2+2+5=9).this i called "piyush contant"with lot of regardspiyushdadriwalawww.piyush-g.741.compkgdwala@rediffmail.comwww.piyushdadriwalamaths.co.in